36-12y+2y^2=20

Solution for 36-12y+2y^2=20 equation:

Simplifying
36 + -12y + 2y2 = 20

Solving
36 + -12y + 2y2 = 20

Solving for variable 'y'.

Reorder the terms:
36 + -20 + -12y + 2y2 = 20 + -20

Combine like terms: 36 + -20 = 16
16 + -12y + 2y2 = 20 + -20

Combine like terms: 20 + -20 = 0
16 + -12y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(8 + -6y + y2) = 0

Factor a trinomial.
2((2 + -1y)(4 + -1y)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(2 + -1y)' equal to zero and attempt to solve:

Simplifying
2 + -1y = 0

Solving
2 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 0 + -2
-1y = 0 + -2

Combine like terms: 0 + -2 = -2
-1y = -2

Divide each side by '-1'.
y = 2

Simplifying
y = 2
Subproblem 2
Set the factor '(4 + -1y)' equal to zero and attempt to solve:

Simplifying
4 + -1y = 0

Solving
4 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = 0 + -4
-1y = 0 + -4

Combine like terms: 0 + -4 = -4
-1y = -4

Divide each side by '-1'.
y = 4

Simplifying
y = 4
Solution
y = {2, 4}